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31129937 is a prime number
BaseRepresentation
bin111011011000…
…0000101010001
32011120120020122
41312300011101
530432124222
63031120025
7525412556
oct166600521
964516218
1031129937
1116632423
12a513015
1365ac3a7
1441c4a2d
152aeda42
hex1db0151

31129937 has 2 divisors, whose sum is σ = 31129938. Its totient is φ = 31129936.

The previous prime is 31129927. The next prime is 31129949. The reversal of 31129937 is 73992113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29855296 + 1274641 = 5464^2 + 1129^2 .

It is a cyclic number.

It is not a de Polignac number, because 31129937 - 212 = 31125841 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 31129897 and 31129906.

It is not a weakly prime, because it can be changed into another prime (31129927) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15564968 + 15564969.

It is an arithmetic number, because the mean of its divisors is an integer number (15564969).

Almost surely, 231129937 is an apocalyptic number.

It is an amenable number.

31129937 is a deficient number, since it is larger than the sum of its proper divisors (1).

31129937 is an equidigital number, since it uses as much as digits as its factorization.

31129937 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10206, while the sum is 35.

The square root of 31129937 is about 5579.4208480809. The cubic root of 31129937 is about 314.5763583598.

The spelling of 31129937 in words is "thirty-one million, one hundred twenty-nine thousand, nine hundred thirty-seven".