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31130010133 = 54756910439
BaseRepresentation
bin11100111111011111…
…100100001000010101
32222100111121100212021
4130333133210020111
51002223240311013
622145000053141
72151300502015
oct347737441025
988314540767
1031130010133
1112225096402
1260494641b1
132c21522551
141714559c45
15c22e3ba8d
hex73f7e4215

31130010133 has 4 divisors (see below), whose sum is σ = 31186921120. Its totient is φ = 31073099148.

The previous prime is 31130010101. The next prime is 31130010143. The reversal of 31130010133 is 33101003113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31130010133 - 25 = 31130010101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31130010143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28454673 + ... + 28455766.

It is an arithmetic number, because the mean of its divisors is an integer number (7796730280).

Almost surely, 231130010133 is an apocalyptic number.

It is an amenable number.

31130010133 is a deficient number, since it is larger than the sum of its proper divisors (56910987).

31130010133 is an equidigital number, since it uses as much as digits as its factorization.

31130010133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56910986.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 31130010133 its reverse (33101003113), we get a palindrome (64231013246).

The spelling of 31130010133 in words is "thirty-one billion, one hundred thirty million, ten thousand, one hundred thirty-three".

Divisors: 1 547 56910439 31130010133