Base | Representation |
---|---|
bin | 100011011001000000011010… |
… | …1010000011011101101000111 |
3 | 1111211020000000211012010222221 |
4 | 1012302000311100123231013 |
5 | 311300320123004124221 |
6 | 3022025145143433211 |
7 | 122366456152230652 |
oct | 10662006520335507 |
9 | 1454200024163887 |
10 | 311300123114311 |
11 | 9020a705a142a1 |
12 | 2aab8071455807 |
13 | 10491625002076 |
14 | 56c30135da899 |
15 | 25ec96d3e5541 |
hex | 11b203541bb47 |
311300123114311 has 2 divisors, whose sum is σ = 311300123114312. Its totient is φ = 311300123114310.
The previous prime is 311300123114291. The next prime is 311300123114329. The reversal of 311300123114311 is 113411321003113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311300123114311 - 29 = 311300123113799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311300123114341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155650061557155 + 155650061557156.
It is an arithmetic number, because the mean of its divisors is an integer number (155650061557156).
Almost surely, 2311300123114311 is an apocalyptic number.
311300123114311 is a deficient number, since it is larger than the sum of its proper divisors (1).
311300123114311 is an equidigital number, since it uses as much as digits as its factorization.
311300123114311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 311300123114311 its reverse (113411321003113), we get a palindrome (424711444117424).
The spelling of 311300123114311 in words is "three hundred eleven trillion, three hundred billion, one hundred twenty-three million, one hundred fourteen thousand, three hundred eleven".
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