Base | Representation |
---|---|
bin | 1110001010000000001100… |
… | …11000010111101100100111 |
3 | 11002020000001022112020222211 |
4 | 13011000012120113230213 |
5 | 13040013300140410343 |
6 | 150112534404104251 |
7 | 6362033110124551 |
oct | 705000630275447 |
9 | 132200038466884 |
10 | 31130030013223 |
11 | 9a12198425499 |
12 | 35a9260095087 |
13 | 144a71a88a5cb |
14 | 7989b6c724d1 |
15 | 38eb6bd3179d |
hex | 1c5006617b27 |
31130030013223 has 2 divisors, whose sum is σ = 31130030013224. Its totient is φ = 31130030013222.
The previous prime is 31130030013107. The next prime is 31130030013293. The reversal of 31130030013223 is 32231003003113.
It is a strong prime.
It is an emirp because it is prime and its reverse (32231003003113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31130030013223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31130030013194 and 31130030013203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31130030013293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565015006611 + 15565015006612.
It is an arithmetic number, because the mean of its divisors is an integer number (15565015006612).
Almost surely, 231130030013223 is an apocalyptic number.
31130030013223 is a deficient number, since it is larger than the sum of its proper divisors (1).
31130030013223 is an equidigital number, since it uses as much as digits as its factorization.
31130030013223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 31130030013223 its reverse (32231003003113), we get a palindrome (63361033016336).
The spelling of 31130030013223 in words is "thirty-one trillion, one hundred thirty billion, thirty million, thirteen thousand, two hundred twenty-three".
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