Base | Representation |
---|---|
bin | 11100111111100000… |
… | …000001101010110001 |
3 | 2222100111211111211022 |
4 | 130333200001222301 |
5 | 1002223303143441 |
6 | 22145002425225 |
7 | 2151301514525 |
oct | 347740015261 |
9 | 88314744738 |
10 | 31130131121 |
11 | 122251692a1 |
12 | 6049502215 |
13 | 2c2156563b |
14 | 171458bd85 |
15 | c22e6284b |
hex | 73f801ab1 |
31130131121 has 4 divisors (see below), whose sum is σ = 31568583744. Its totient is φ = 30691678500.
The previous prime is 31130131079. The next prime is 31130131133. The reversal of 31130131121 is 12113103113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12113103113 = 6521 ⋅1857553.
It is a cyclic number.
It is not a de Polignac number, because 31130131121 - 234 = 13950261937 is a prime.
It is a super-2 number, since 2×311301311212 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 31130131121.
It is not an unprimeable number, because it can be changed into a prime (31130131181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219226205 + ... + 219226346.
It is an arithmetic number, because the mean of its divisors is an integer number (7892145936).
Almost surely, 231130131121 is an apocalyptic number.
It is an amenable number.
31130131121 is a deficient number, since it is larger than the sum of its proper divisors (438452623).
31130131121 is an equidigital number, since it uses as much as digits as its factorization.
31130131121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 438452622.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 31130131121 its reverse (12113103113), we get a palindrome (43243234234).
The spelling of 31130131121 in words is "thirty-one billion, one hundred thirty million, one hundred thirty-one thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •