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31131020000001 = 323344536509299
BaseRepresentation
bin1110001010000010000010…
…11000110111101100000001
311002020002121022100210112210
413011001001120313230001
513040022312110000001
6150113220531012333
76362066460642435
oct705010130675401
9132202538323483
1031131020000001
119a1265622a189
1235a949773a0a9
13144a8479ccbbc
14798a6c5349c5
1538ebc8bd5dd6
hex1c5041637b01

31131020000001 has 8 divisors (see below), whose sum is σ = 41686172704800. Its totient is φ = 20664940314272.

The previous prime is 31131019999993. The next prime is 31131020000039. The reversal of 31131020000001 is 10000002013113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31131020000001 - 23 = 31131019999993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (31131020000071) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22268253951 + ... + 22268255348.

It is an arithmetic number, because the mean of its divisors is an integer number (5210771588100).

Almost surely, 231131020000001 is an apocalyptic number.

It is an amenable number.

31131020000001 is a deficient number, since it is larger than the sum of its proper divisors (10555152704799).

31131020000001 is a wasteful number, since it uses less digits than its factorization.

31131020000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44536509535.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 31131020000001 its reverse (10000002013113), we get a palindrome (41131022013114).

The spelling of 31131020000001 in words is "thirty-one trillion, one hundred thirty-one billion, twenty million, one", and thus it is an aban number.

Divisors: 1 3 233 699 44536509299 133609527897 10377006666667 31131020000001