Base | Representation |
---|---|
bin | 1110001010000010000010… |
… | …11000110111101100100111 |
3 | 11002020002121022100210121012 |
4 | 13011001001120313230213 |
5 | 13040022312110000124 |
6 | 150113220531012435 |
7 | 6362066460642521 |
oct | 705010130675447 |
9 | 132202538323535 |
10 | 31131020000039 |
11 | 9a1265622a213 |
12 | 35a949773a11b |
13 | 144a8479ccc1b |
14 | 798a6c534a11 |
15 | 38ebc8bd5e0e |
hex | 1c5041637b27 |
31131020000039 has 2 divisors, whose sum is σ = 31131020000040. Its totient is φ = 31131020000038.
The previous prime is 31131019999993. The next prime is 31131020000057. The reversal of 31131020000039 is 93000002013113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31131020000039 - 240 = 30031508372263 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31131019999969 and 31131020000023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31131020002039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565510000019 + 15565510000020.
It is an arithmetic number, because the mean of its divisors is an integer number (15565510000020).
Almost surely, 231131020000039 is an apocalyptic number.
31131020000039 is a deficient number, since it is larger than the sum of its proper divisors (1).
31131020000039 is an equidigital number, since it uses as much as digits as its factorization.
31131020000039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 23.
The spelling of 31131020000039 in words is "thirty-one trillion, one hundred thirty-one billion, twenty million, thirty-nine", and thus it is an aban number.
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