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31131023211997 is a prime number
BaseRepresentation
bin1110001010000010000011…
…00101000111110111011101
311002020002121112101222120121
413011001001211013313131
513040022313420240442
6150113221123514541
76362066530151032
oct705010145076735
9132202545358517
1031131023211997
119a12658023425
1235a9498828a51
13144a848585ba7
14798a6cb2d389
1538ebc911c967
hex1c5041947ddd

31131023211997 has 2 divisors, whose sum is σ = 31131023211998. Its totient is φ = 31131023211996.

The previous prime is 31131023211989. The next prime is 31131023212057. The reversal of 31131023211997 is 79911232013113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29471283132516 + 1659740079481 = 5428746^2 + 1288309^2 .

It is a cyclic number.

It is not a de Polignac number, because 31131023211997 - 23 = 31131023211989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31131023211697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565511605998 + 15565511605999.

It is an arithmetic number, because the mean of its divisors is an integer number (15565511605999).

Almost surely, 231131023211997 is an apocalyptic number.

It is an amenable number.

31131023211997 is a deficient number, since it is larger than the sum of its proper divisors (1).

31131023211997 is an equidigital number, since it uses as much as digits as its factorization.

31131023211997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61236, while the sum is 43.

The spelling of 31131023211997 in words is "thirty-one trillion, one hundred thirty-one billion, twenty-three million, two hundred eleven thousand, nine hundred ninety-seven".