Base | Representation |
---|---|
bin | 1011100110001110… |
… | …0011010000100001 |
3 | 22000221212002102121 |
4 | 2321203203100201 |
5 | 22333423320132 |
6 | 1232524344241 |
7 | 140100644113 |
oct | 27143432041 |
9 | 8027762377 |
10 | 3113104417 |
11 | 13582a2475 |
12 | 72a6a5081 |
13 | 3a7c65927 |
14 | 2176493b3 |
15 | 133486497 |
hex | b98e3421 |
3113104417 has 2 divisors, whose sum is σ = 3113104418. Its totient is φ = 3113104416.
The previous prime is 3113104399. The next prime is 3113104453. The reversal of 3113104417 is 7144013113.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1991926161 + 1121178256 = 44631^2 + 33484^2 .
It is a cyclic number.
It is not a de Polignac number, because 3113104417 - 231 = 965620769 is a prime.
It is a super-2 number, since 2×31131044172 = 19382838222289819778, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3113104391 and 3113104400.
It is not a weakly prime, because it can be changed into another prime (3113134417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556552208 + 1556552209.
It is an arithmetic number, because the mean of its divisors is an integer number (1556552209).
Almost surely, 23113104417 is an apocalyptic number.
It is an amenable number.
3113104417 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113104417 is an equidigital number, since it uses as much as digits as its factorization.
3113104417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
The square root of 3113104417 is about 55795.2006627810. The cubic root of 3113104417 is about 1460.1514224946.
The spelling of 3113104417 in words is "three billion, one hundred thirteen million, one hundred four thousand, four hundred seventeen".
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