Base | Representation |
---|---|
bin | 101101010011010100000… |
… | …000100010011001110011 |
3 | 102000121111012202212122112 |
4 | 231103110000202121303 |
5 | 402001123441424021 |
6 | 10342051112355535 |
7 | 440625563605445 |
oct | 55232400423163 |
9 | 12017435685575 |
10 | 3113113233011 |
11 | aa029a296931 |
12 | 4234133a5bab |
13 | 197747009102 |
14 | aa96575a495 |
15 | 55ea4cead5b |
hex | 2d4d4022673 |
3113113233011 has 4 divisors (see below), whose sum is σ = 3113138653800. Its totient is φ = 3113087812224.
The previous prime is 3113113233001. The next prime is 3113113233031. The reversal of 3113113233011 is 1103323113113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3113113233011 - 218 = 3113112970867 is a prime.
It is a super-2 number, since 2×31131132330112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3113113233001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12525806 + ... + 12771923.
It is an arithmetic number, because the mean of its divisors is an integer number (778284663450).
Almost surely, 23113113233011 is an apocalyptic number.
3113113233011 is a deficient number, since it is larger than the sum of its proper divisors (25420789).
3113113233011 is a wasteful number, since it uses less digits than its factorization.
3113113233011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25420788.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 3113113233011 its reverse (1103323113113), we get a palindrome (4216436346124).
The spelling of 3113113233011 in words is "three trillion, one hundred thirteen billion, one hundred thirteen million, two hundred thirty-three thousand, eleven".
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