311320012022113 has 2 divisors, whose sum is σ = 311320012022114. Its totient is φ = 311320012022112.

The previous prime is 311320012022087. The next prime is 311320012022119. The reversal of 311320012022113 is 311220210023113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 177102411528289 + 134217600493824 = 13307983^2 + 11585232^2 .

It is a cyclic number.

It is not a de Polignac number, because 311320012022113 - 2¹³ = 311320012013921 is a prime.

It is not a weakly prime, because it can be changed into another prime (311320012022119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155660006011056 + 155660006011057.

It is an arithmetic number, because the mean of its divisors is an integer number (155660006011057).

Almost surely, 2^{311320012022113} is an apocalyptic number.

It is an amenable number.

311320012022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

311320012022113 is an equidigital number, since it uses as much as digits as its factorization.

311320012022113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 311320012022113 its reverse (311220210023113), we get a palindrome (622540222045226).

The spelling of 311320012022113 in words is "three hundred eleven trillion, three hundred twenty billion, twelve million, twenty-two thousand, one hundred thirteen".