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31132021114 = 215566010557
BaseRepresentation
bin11100111111100111…
…001111000101111010
32222100122101112102001
4130333213033011322
51002224244133424
622145111131214
72151323545645
oct347747170572
988318345361
1031132021114
111222623a277
12604a073b0a
132c21a7798c
141714920a5c
15c231d7844
hex73f9cf17a

31132021114 has 4 divisors (see below), whose sum is σ = 46698031674. Its totient is φ = 15566010556.

The previous prime is 31132021097. The next prime is 31132021153. The reversal of 31132021114 is 41112023113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41112023113 = 75873146159.

It can be written as a sum of positive squares in only one way, i.e., 31075696089 + 56325025 = 176283^2 + 7505^2 .

It is a junction number, because it is equal to n+sod(n) for n = 31132021091 and 31132021100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7783005277 + ... + 7783005280.

Almost surely, 231132021114 is an apocalyptic number.

31132021114 is a deficient number, since it is larger than the sum of its proper divisors (15566010560).

31132021114 is a wasteful number, since it uses less digits than its factorization.

31132021114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15566010559.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 31132021114 its reverse (41112023113), we get a palindrome (72244044227).

The spelling of 31132021114 in words is "thirty-one billion, one hundred thirty-two million, twenty-one thousand, one hundred fourteen".

Divisors: 1 2 15566010557 31132021114