31132113 has 4 divisors (see below), whose sum is σ = 41509488. Its totient is φ = 20754740.

The previous prime is 31132103. The next prime is 31132141. The reversal of 31132113 is 31123113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31132113 - 2⁴ = 31132097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31132092 and 31132101.

It is not an unprimeable number, because it can be changed into a prime (31132103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5188683 + ... + 5188688.

It is an arithmetic number, because the mean of its divisors is an integer number (10377372).

Almost surely, 2^31132113 is an apocalyptic number.

It is an amenable number.

31132113 is a deficient number, since it is larger than the sum of its proper divisors (10377375).

31132113 is a wasteful number, since it uses less digits than its factorization.

31132113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10377374.

The product of its digits is 54, while the sum is 15.

The square root of 31132113 is about 5579.6158469916. The cubic root of 31132113 is about 314.5836878768.

Adding to 31132113 its reverse (31123113), we get a palindrome (62255226).

The spelling of 31132113 in words is "thirty-one million, one hundred thirty-two thousand, one hundred thirteen".