3113214104401 has 2 divisors, whose sum is σ = 3113214104402. Its totient is φ = 3113214104400.

The previous prime is 3113214104383. The next prime is 3113214104419. The reversal of 3113214104401 is 1044014123113.

It is a balanced prime because it is at equal distance from previous prime (3113214104383) and next prime (3113214104419).

It can be written as a sum of positive squares in only one way, i.e., 2858314329025 + 254899775376 = 1690655^2 + 504876^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113214104401 - 2²⁹ = 3112677233489 is a prime.

It is not a weakly prime, because it can be changed into another prime (3113214104431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556607052200 + 1556607052201.

It is an arithmetic number, because the mean of its divisors is an integer number (1556607052201).

Almost surely, 2^{3113214104401} is an apocalyptic number.

It is an amenable number.

3113214104401 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113214104401 is an equidigital number, since it uses as much as digits as its factorization.

3113214104401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 3113214104401 its reverse (1044014123113), we get a palindrome (4157228227514).

The spelling of 3113214104401 in words is "three trillion, one hundred thirteen billion, two hundred fourteen million, one hundred four thousand, four hundred one".