311322540231 has 36 divisors (see below), whose sum is σ = 468556698792. Its totient is φ = 206838726768.

The previous prime is 311322540223. The next prime is 311322540239. The reversal of 311322540231 is 132045223113.

311322540231 is a `hidden beast` number, since 3 + 1 + 1 + 3 + 225 + 402 + 31 = 666.

It is an interprime number because it is at equal distance from previous prime (311322540223) and next prime (311322540239).

It is not a de Polignac number, because 311322540231 - 2³ = 311322540223 is a prime.

It is a super-2 number, since 2×311322540231² (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 311322540195 and 311322540204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311322540239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1841400 + ... + 2003346.

Almost surely, 2^311322540231 is an apocalyptic number.

311322540231 is a deficient number, since it is larger than the sum of its proper divisors (157234158561).

311322540231 is an frugal number, since it uses more digits than its factorization.

311322540231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162264 (or 162243 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 311322540231 its reverse (132045223113), we get a palindrome (443367763344).

The spelling of 311322540231 in words is "three hundred eleven billion, three hundred twenty-two million, five hundred forty thousand, two hundred thirty-one".