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31132414141 = 83375089327
BaseRepresentation
bin11100111111101000…
…101111000010111101
32222100200010111112121
4130333220233002331
51002224344223031
622145123402541
72151330103543
oct347750570275
988320114477
1031132414141
1112226488594
12604a223451
132c21b8483a
1417149c3d93
15c23264011
hex73fa2f0bd

31132414141 has 4 divisors (see below), whose sum is σ = 31507503552. Its totient is φ = 30757324732.

The previous prime is 31132414121. The next prime is 31132414153. The reversal of 31132414141 is 14141423113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31132414141 - 211 = 31132412093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31132414111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187544581 + ... + 187544746.

It is an arithmetic number, because the mean of its divisors is an integer number (7876875888).

Almost surely, 231132414141 is an apocalyptic number.

It is an amenable number.

31132414141 is a deficient number, since it is larger than the sum of its proper divisors (375089411).

31132414141 is an equidigital number, since it uses as much as digits as its factorization.

31132414141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 375089410.

The product of its digits is 1152, while the sum is 25.

Adding to 31132414141 its reverse (14141423113), we get a palindrome (45273837254).

The spelling of 31132414141 in words is "thirty-one billion, one hundred thirty-two million, four hundred fourteen thousand, one hundred forty-one".

Divisors: 1 83 375089327 31132414141