311324404541 has 4 divisors (see below), whose sum is σ = 311325541500. Its totient is φ = 311323267584.

The previous prime is 311324404507. The next prime is 311324404553. The reversal of 311324404541 is 145404423113.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 145404423113 = 33457 ⋅4346009.

It can be written as a sum of positive squares in 2 ways, for example, as 183175440100 + 128148964441 = 427990^2 + 357979^2 .

It is a cyclic number.

It is not a de Polignac number, because 311324404541 - 2¹⁰ = 311324403517 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311324404498 and 311324404507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311324404241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120995 + ... + 798303.

It is an arithmetic number, because the mean of its divisors is an integer number (77831385375).

Almost surely, 2^311324404541 is an apocalyptic number.

It is an amenable number.

311324404541 is a deficient number, since it is larger than the sum of its proper divisors (1136959).

311324404541 is an equidigital number, since it uses as much as digits as its factorization.

311324404541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1136958.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 311324404541 its reverse (145404423113), we get a palindrome (456728827654).

The spelling of 311324404541 in words is "three hundred eleven billion, three hundred twenty-four million, four hundred four thousand, five hundred forty-one".