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31133304014401 is a prime number
BaseRepresentation
bin1110001010000110010011…
…00001101100011001000001
311002020022111111010202021201
413011003021201230121001
513040042001311430101
6150114235321221201
76362210203514521
oct705031141543101
9132208444122251
1031133304014401
119a13618521a96
1235a9a14631801
13144ab1cc68c04
14798c07a01681
1538ecae49ae01
hex1c50c986c641

31133304014401 has 2 divisors, whose sum is σ = 31133304014402. Its totient is φ = 31133304014400.

The previous prime is 31133304014399. The next prime is 31133304014521. The reversal of 31133304014401 is 10441040333113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20481272589376 + 10652031425025 = 4525624^2 + 3263745^2 .

It is a cyclic number.

It is not a de Polignac number, because 31133304014401 - 21 = 31133304014399 is a prime.

Together with 31133304014399, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 31133304014401.

It is not a weakly prime, because it can be changed into another prime (31133304012401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15566652007200 + 15566652007201.

It is an arithmetic number, because the mean of its divisors is an integer number (15566652007201).

Almost surely, 231133304014401 is an apocalyptic number.

It is an amenable number.

31133304014401 is a deficient number, since it is larger than the sum of its proper divisors (1).

31133304014401 is an equidigital number, since it uses as much as digits as its factorization.

31133304014401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 31133304014401 its reverse (10441040333113), we get a palindrome (41574344347514).

The spelling of 31133304014401 in words is "thirty-one trillion, one hundred thirty-three billion, three hundred four million, fourteen thousand, four hundred one".