311342343243131 has 2 divisors, whose sum is σ = 311342343243132. Its totient is φ = 311342343243130.

The previous prime is 311342343243103. The next prime is 311342343243133. The reversal of 311342343243131 is 131342343243113.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311342343243131 is a prime.

It is a super-3 number, since 3×311342343243131³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 311342343243133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (311342343243133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155671171621565 + 155671171621566.

It is an arithmetic number, because the mean of its divisors is an integer number (155671171621566).

Almost surely, 2^{311342343243131} is an apocalyptic number.

311342343243131 is a deficient number, since it is larger than the sum of its proper divisors (1).

311342343243131 is an equidigital number, since it uses as much as digits as its factorization.

311342343243131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 186624, while the sum is 38.

Adding to 311342343243131 its reverse (131342343243113), we get a palindrome (442684686486244).

The spelling of 311342343243131 in words is "three hundred eleven trillion, three hundred forty-two billion, three hundred forty-three million, two hundred forty-three thousand, one hundred thirty-one".