Base | Representation |
---|---|
bin | 1110001010001010000111… |
… | …10010111011100000011001 |
3 | 11002020111210110002112222120 |
4 | 13011011003302323200121 |
5 | 13040110201432244423 |
6 | 150115215040411453 |
7 | 6362312062561044 |
oct | 705050362734031 |
9 | 132214713075876 |
10 | 31135355353113 |
11 | 9a14480444140 |
12 | 35aa2a7616b89 |
13 | 144b088c49abb |
14 | 798d60221c5b |
15 | 38ed7e5eeee3 |
hex | 1c5143cbb819 |
31135355353113 has 8 divisors (see below), whose sum is σ = 45287789604576. Its totient is φ = 18869912335200.
The previous prime is 31135355353111. The next prime is 31135355353127.
31135355353113 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31135355353113 - 21 = 31135355353111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31135355353111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 471747808348 + ... + 471747808413.
It is an arithmetic number, because the mean of its divisors is an integer number (5660973700572).
Almost surely, 231135355353113 is an apocalyptic number.
31135355353113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31135355353113 is a deficient number, since it is larger than the sum of its proper divisors (14152434251463).
31135355353113 is a wasteful number, since it uses less digits than its factorization.
31135355353113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 943495616775.
The product of its digits is 455625, while the sum is 42.
It can be divided in two parts, 3113535 and 5353113, that added together give a palindrome (8466648).
The spelling of 31135355353113 in words is "thirty-one trillion, one hundred thirty-five billion, three hundred fifty-five million, three hundred fifty-three thousand, one hundred thirteen".
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