311354202453113 has 4 divisors (see below), whose sum is σ = 311899481267088. Its totient is φ = 310808923639140.

The previous prime is 311354202453101. The next prime is 311354202453181.

It is a happy number.

311354202453113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311354202453113 - 2¹⁴ = 311354202436729 is a prime.

It is a super-3 number, since 3×311354202453113³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311354102453113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272639406131 + ... + 272639407272.

It is an arithmetic number, because the mean of its divisors is an integer number (77974870316772).

Almost surely, 2^{311354202453113} is an apocalyptic number.

It is an amenable number.

311354202453113 is a deficient number, since it is larger than the sum of its proper divisors (545278813975).

311354202453113 is an equidigital number, since it uses as much as digits as its factorization.

311354202453113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 545278813974.

The product of its (nonzero) digits is 129600, while the sum is 38.

It can be divided in two parts, 31135420 and 2453113, that added together give a palindrome (33588533).

The spelling of 311354202453113 in words is "three hundred eleven trillion, three hundred fifty-four billion, two hundred two million, four hundred fifty-three thousand, one hundred thirteen".