Base | Representation |
---|---|
bin | 101101010011110111010… |
… | …010010011101110110011 |
3 | 102000200000110110112101101 |
4 | 231103313102103232303 |
5 | 402003332001002232 |
6 | 10342225534145231 |
7 | 440646341416051 |
oct | 55236722235663 |
9 | 12020013415341 |
10 | 3113705094067 |
11 | aa05733958a7 |
12 | 423559652217 |
13 | 19780c815259 |
14 | aa9c01c51d1 |
15 | 55edbc5c1e7 |
hex | 2d4f7493bb3 |
3113705094067 has 2 divisors, whose sum is σ = 3113705094068. Its totient is φ = 3113705094066.
The previous prime is 3113705094037. The next prime is 3113705094113. The reversal of 3113705094067 is 7604905073113.
It is an a-pointer prime, because the next prime (3113705094113) can be obtained adding 3113705094067 to its sum of digits (46).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3113705094067 - 231 = 3111557610419 is a prime.
It is not a weakly prime, because it can be changed into another prime (3113705094037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556852547033 + 1556852547034.
It is an arithmetic number, because the mean of its divisors is an integer number (1556852547034).
Almost surely, 23113705094067 is an apocalyptic number.
3113705094067 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113705094067 is an equidigital number, since it uses as much as digits as its factorization.
3113705094067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 476280, while the sum is 46.
The spelling of 3113705094067 in words is "three trillion, one hundred thirteen billion, seven hundred five million, ninety-four thousand, sixty-seven".
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