Base | Representation |
---|---|
bin | 1001000011111111011… |
… | …11101011000111001001 |
3 | 1002202201200000001201122 |
4 | 10201333233223013021 |
5 | 20100201444132342 |
6 | 355014004125025 |
7 | 31332210355403 |
oct | 4417757530711 |
9 | 1082650001648 |
10 | 311380849097 |
11 | 11006840a70a |
12 | 50420996775 |
13 | 23494920a46 |
14 | 110dc82db73 |
15 | 81768cc4d2 |
hex | 487fbeb1c9 |
311380849097 has 2 divisors, whose sum is σ = 311380849098. Its totient is φ = 311380849096.
The previous prime is 311380849019. The next prime is 311380849127. The reversal of 311380849097 is 790948083113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 309808012816 + 1572836281 = 556604^2 + 39659^2 .
It is a cyclic number.
It is not a de Polignac number, because 311380849097 - 212 = 311380845001 is a prime.
It is not a weakly prime, because it can be changed into another prime (311380849007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155690424548 + 155690424549.
It is an arithmetic number, because the mean of its divisors is an integer number (155690424549).
Almost surely, 2311380849097 is an apocalyptic number.
It is an amenable number.
311380849097 is a deficient number, since it is larger than the sum of its proper divisors (1).
311380849097 is an equidigital number, since it uses as much as digits as its factorization.
311380849097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 53.
The spelling of 311380849097 in words is "three hundred eleven billion, three hundred eighty million, eight hundred forty-nine thousand, ninety-seven".
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