Base | Representation |
---|---|
bin | 100011011001110000100000… |
… | …1110100000100111110101011 |
3 | 1111211120212122021100000010201 |
4 | 1012303201001310010332223 |
5 | 311304013142212000412 |
6 | 3022144430352253031 |
7 | 122410103604615151 |
oct | 10663410164047653 |
9 | 1454525567300121 |
10 | 311403413000107 |
11 | 9024a49a40627a |
12 | 2ab14098b41177 |
13 | 1049b2a629229c |
14 | 56c80115633d1 |
15 | 26004b6385e57 |
hex | 11b3841d04fab |
311403413000107 has 2 divisors, whose sum is σ = 311403413000108. Its totient is φ = 311403413000106.
The previous prime is 311403412999979. The next prime is 311403413000123. The reversal of 311403413000107 is 701000314304113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311403413000107 - 27 = 311403412999979 is a prime.
It is a super-2 number, since 2×3114034130001072 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311403413000137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155701706500053 + 155701706500054.
It is an arithmetic number, because the mean of its divisors is an integer number (155701706500054).
Almost surely, 2311403413000107 is an apocalyptic number.
311403413000107 is a deficient number, since it is larger than the sum of its proper divisors (1).
311403413000107 is an equidigital number, since it uses as much as digits as its factorization.
311403413000107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 28.
The spelling of 311403413000107 in words is "three hundred eleven trillion, four hundred three billion, four hundred thirteen million, one hundred seven", and thus it is an aban number.
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