Base | Representation |
---|---|
bin | 100011011001110011101011… |
… | …1101010011001111010100001 |
3 | 1111211121112012210200202101122 |
4 | 1012303213113222121322201 |
5 | 311304121113313422423 |
6 | 3022151514145142025 |
7 | 122410434414362015 |
oct | 10663472752317241 |
9 | 1454545183622348 |
10 | 311410222014113 |
11 | 90252373974282 |
12 | 2ab1547932a915 |
13 | 1049bb1cb48a61 |
14 | 56c84999a6545 |
15 | 26007640268c8 |
hex | 11b39d7a99ea1 |
311410222014113 has 4 divisors (see below), whose sum is σ = 311445938300160. Its totient is φ = 311374505728068.
The previous prime is 311410222014109. The next prime is 311410222014173.
It is a happy number.
311410222014113 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 311410222014113 - 22 = 311410222014109 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (311410222014173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17858129945 + ... + 17858147382.
It is an arithmetic number, because the mean of its divisors is an integer number (77861484575040).
Almost surely, 2311410222014113 is an apocalyptic number.
It is an amenable number.
311410222014113 is a deficient number, since it is larger than the sum of its proper divisors (35716286047).
311410222014113 is an equidigital number, since it uses as much as digits as its factorization.
311410222014113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35716286046.
The product of its (nonzero) digits is 1152, while the sum is 26.
The spelling of 311410222014113 in words is "three hundred eleven trillion, four hundred ten billion, two hundred twenty-two million, fourteen thousand, one hundred thirteen".
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