3114111111113 has 2 divisors, whose sum is σ = 3114111111114. Its totient is φ = 3114111111112.

The previous prime is 3114111111043. The next prime is 3114111111149. The reversal of 3114111111113 is 3111111114113.

It is a happy number.

It is a m-pointer prime, because the next prime (3114111111149) can be obtained adding 3114111111113 to its product of digits (36).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2137990822969 + 976120288144 = 1462187^2 + 987988^2 .

It is a cyclic number.

It is not a de Polignac number, because 3114111111113 - 2¹⁸ = 3114110848969 is a prime.

It is not a weakly prime, because it can be changed into another prime (3114111011113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557055555556 + 1557055555557.

It is an arithmetic number, because the mean of its divisors is an integer number (1557055555557).

Almost surely, 2^{3114111111113} is an apocalyptic number.

It is an amenable number.

3114111111113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3114111111113 is an equidigital number, since it uses as much as digits as its factorization.

3114111111113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36, while the sum is 20.

Adding to 3114111111113 its reverse (3111111114113), we get a palindrome (6225222225226).

The spelling of 3114111111113 in words is "three trillion, one hundred fourteen billion, one hundred eleven million, one hundred eleven thousand, one hundred thirteen".