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3114112024411 = 6232749964093
BaseRepresentation
bin101101010100001111100…
…010100111111101011011
3102000201001211011201212121
4231110033202213331123
5402010200134240121
610342334152122111
7440662412313643
oct55241742477533
912021054151777
103114112024411
11aa0762064673
12423651996337
13197875c1213b
14aaa1c271523
155601283e141
hex2d50f8a7f5b

3114112024411 has 4 divisors (see below), whose sum is σ = 3114162050832. Its totient is φ = 3114061997992.

The previous prime is 3114112024393. The next prime is 3114112024427. The reversal of 3114112024411 is 1144202114113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3114112024411 - 237 = 2976673070939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3114112024211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24919720 + ... + 25044373.

It is an arithmetic number, because the mean of its divisors is an integer number (778540512708).

Almost surely, 23114112024411 is an apocalyptic number.

3114112024411 is a deficient number, since it is larger than the sum of its proper divisors (50026421).

3114112024411 is an equidigital number, since it uses as much as digits as its factorization.

3114112024411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50026420.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 3114112024411 its reverse (1144202114113), we get a palindrome (4258314138524).

The spelling of 3114112024411 in words is "three trillion, one hundred fourteen billion, one hundred twelve million, twenty-four thousand, four hundred eleven".

Divisors: 1 62327 49964093 3114112024411