Base | Representation |
---|---|
bin | 100011011001110100001111… |
… | …0101110101010110011101111 |
3 | 1111211121122021220012212122222 |
4 | 1012303220132232222303233 |
5 | 311304131034031023343 |
6 | 3022152232340225555 |
7 | 122410506102640436 |
oct | 10663503656526357 |
9 | 1454548256185588 |
10 | 311411414314223 |
11 | 902529259a0a73 |
12 | 2ab1575069b2bb |
13 | 1049bc7cb75592 |
14 | 56c857009011d |
15 | 26007d3a40a68 |
hex | 11b3a1ebaacef |
311411414314223 has 2 divisors, whose sum is σ = 311411414314224. Its totient is φ = 311411414314222.
The previous prime is 311411414314213. The next prime is 311411414314261. The reversal of 311411414314223 is 322413414114113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 311411414314223 - 210 = 311411414313199 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311411414314213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155705707157111 + 155705707157112.
It is an arithmetic number, because the mean of its divisors is an integer number (155705707157112).
Almost surely, 2311411414314223 is an apocalyptic number.
311411414314223 is a deficient number, since it is larger than the sum of its proper divisors (1).
311411414314223 is an equidigital number, since it uses as much as digits as its factorization.
311411414314223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 27648, while the sum is 35.
Adding to 311411414314223 its reverse (322413414114113), we get a palindrome (633824828428336).
The spelling of 311411414314223 in words is "three hundred eleven trillion, four hundred eleven billion, four hundred fourteen million, three hundred fourteen thousand, two hundred twenty-three".
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