311411540003423 has 2 divisors, whose sum is σ = 311411540003424. Its totient is φ = 311411540003422.

The previous prime is 311411540003413. The next prime is 311411540003471. The reversal of 311411540003423 is 324300045114113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311411540003423 - 2⁶ = 311411540003359 is a prime.

It is a super-3 number, since 3×311411540003423³ (a number of 44 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 311411540003423.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311411540003413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155705770001711 + 155705770001712.

It is an arithmetic number, because the mean of its divisors is an integer number (155705770001712).

Almost surely, 2^{311411540003423} is an apocalyptic number.

311411540003423 is a deficient number, since it is larger than the sum of its proper divisors (1).

311411540003423 is an equidigital number, since it uses as much as digits as its factorization.

311411540003423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 311411540003423 its reverse (324300045114113), we get a palindrome (635711585117536).

The spelling of 311411540003423 in words is "three hundred eleven trillion, four hundred eleven billion, five hundred forty million, three thousand, four hundred twenty-three".