Base | Representation |
---|---|
bin | 11101000000001010… |
… | …111001100010001001 |
3 | 2222101021222111122211 |
4 | 131000022321202021 |
5 | 1002234142314433 |
6 | 22150043345121 |
7 | 2151466164106 |
oct | 350012714211 |
9 | 88337874584 |
10 | 31141369993 |
11 | 12230545218 |
12 | 60512221a1 |
13 | 2c2399c066 |
14 | 1715c75aad |
15 | c23e328cd |
hex | 7402b9889 |
31141369993 has 2 divisors, whose sum is σ = 31141369994. Its totient is φ = 31141369992.
The previous prime is 31141369991. The next prime is 31141369997. The reversal of 31141369993 is 39996314113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25241901129 + 5899468864 = 158877^2 + 76808^2 .
It is a cyclic number.
It is not a de Polignac number, because 31141369993 - 21 = 31141369991 is a prime.
Together with 31141369991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (31141369991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15570684996 + 15570684997.
It is an arithmetic number, because the mean of its divisors is an integer number (15570684997).
Almost surely, 231141369993 is an apocalyptic number.
It is an amenable number.
31141369993 is a deficient number, since it is larger than the sum of its proper divisors (1).
31141369993 is an equidigital number, since it uses as much as digits as its factorization.
31141369993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 472392, while the sum is 49.
The spelling of 31141369993 in words is "thirty-one billion, one hundred forty-one million, three hundred sixty-nine thousand, nine hundred ninety-three".
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