Base | Representation |
---|---|
bin | 1001000100000100001… |
… | …01000100011001111001 |
3 | 1002202211101200202100012 |
4 | 10202002011010121321 |
5 | 20100242010342103 |
6 | 355021523351305 |
7 | 31333164266405 |
oct | 4420205043171 |
9 | 1082741622305 |
10 | 311420012153 |
11 | 110088529478 |
12 | 50431b22535 |
13 | 2349ca83653 |
14 | 11103b06105 |
15 | 817a0662d8 |
hex | 4882144679 |
311420012153 has 2 divisors, whose sum is σ = 311420012154. Its totient is φ = 311420012152.
The previous prime is 311420012147. The next prime is 311420012171. The reversal of 311420012153 is 351210024113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 192503317504 + 118916694649 = 438752^2 + 344843^2 .
It is a cyclic number.
It is not a de Polignac number, because 311420012153 - 210 = 311420011129 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (311420011153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155710006076 + 155710006077.
It is an arithmetic number, because the mean of its divisors is an integer number (155710006077).
Almost surely, 2311420012153 is an apocalyptic number.
It is an amenable number.
311420012153 is a deficient number, since it is larger than the sum of its proper divisors (1).
311420012153 is an equidigital number, since it uses as much as digits as its factorization.
311420012153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 311420012153 its reverse (351210024113), we get a palindrome (662630036266).
The spelling of 311420012153 in words is "three hundred eleven billion, four hundred twenty million, twelve thousand, one hundred fifty-three".
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