Base | Representation |
---|---|
bin | 1110001010010110111000… |
… | …11100000000001000110001 |
3 | 11002021011111020121212221201 |
4 | 13011023130130000020301 |
5 | 13040213222033132423 |
6 | 150122311225451201 |
7 | 6362644011532123 |
oct | 705133434001061 |
9 | 132234436555851 |
10 | 31142211224113 |
11 | 9a173793a6530 |
12 | 35ab69b640b01 |
13 | 144b90c42b1c2 |
14 | 799410981213 |
15 | 3901314492ad |
hex | 1c52dc700231 |
31142211224113 has 16 divisors (see below), whose sum is σ = 36650464315776. Its totient is φ = 26142992362240.
The previous prime is 31142211224041. The next prime is 31142211224119.
31142211224113 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 31142211224113 - 241 = 28943187968561 is a prime.
It is a super-3 number, since 3×311422112241133 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31142211224119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1571083381 + ... + 1571103202.
It is an arithmetic number, because the mean of its divisors is an integer number (2290654019736).
Almost surely, 231142211224113 is an apocalyptic number.
It is an amenable number.
31142211224113 is a deficient number, since it is larger than the sum of its proper divisors (5508253091663).
31142211224113 is a wasteful number, since it uses less digits than its factorization.
31142211224113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3142186664.
The product of its digits is 2304, while the sum is 28.
It can be divided in two parts, 3114221 and 1224113, that added together give a palindrome (4338334).
The spelling of 31142211224113 in words is "thirty-one trillion, one hundred forty-two billion, two hundred eleven million, two hundred twenty-four thousand, one hundred thirteen".
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