Base | Representation |
---|---|
bin | 1110001010010111000110… |
… | …00011110100001010010001 |
3 | 11002021011202222200100111112 |
4 | 13011023203003310022101 |
5 | 13040213434003332423 |
6 | 150122330235023105 |
7 | 6362646531054620 |
oct | 705134303641221 |
9 | 132234688610445 |
10 | 31142322324113 |
11 | 9a17426089610 |
12 | 35ab71089aa95 |
13 | 144b92945a150 |
14 | 7994216216b7 |
15 | 39013b092a78 |
hex | 1c52e30f4291 |
31142322324113 has 16 divisors (see below), whose sum is σ = 41813467737216. Its totient is φ = 22400072000640.
The previous prime is 31142322324079. The next prime is 31142322324149.
31142322324113 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 31142322324113 - 212 = 31142322320017 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31142322324113.
It is not an unprimeable number, because it can be changed into a prime (31142322324713) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15555604556 + ... + 15555606557.
It is an arithmetic number, because the mean of its divisors is an integer number (2613341733576).
Almost surely, 231142322324113 is an apocalyptic number.
It is an amenable number.
31142322324113 is a deficient number, since it is larger than the sum of its proper divisors (10671145413103).
31142322324113 is a wasteful number, since it uses less digits than its factorization.
31142322324113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31111211144.
The product of its digits is 20736, while the sum is 32.
It can be divided in two parts, 3114232 and 2324113, that added together give a palindrome (5438345).
The spelling of 31142322324113 in words is "thirty-one trillion, one hundred forty-two billion, three hundred twenty-two million, three hundred twenty-four thousand, one hundred thirteen".
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