Base | Representation |
---|---|
bin | 11101000000001110… |
… | …111111110110110111 |
3 | 2222101101000002120022 |
4 | 131000032333312313 |
5 | 1002234431210341 |
6 | 22150122355355 |
7 | 2151511260515 |
oct | 350016776667 |
9 | 88341002508 |
10 | 31142444471 |
11 | 12231109516 |
12 | 605165bb5b |
13 | 2c23c87148 |
14 | 17160754b5 |
15 | c24095e4b |
hex | 7403bfdb7 |
31142444471 has 2 divisors, whose sum is σ = 31142444472. Its totient is φ = 31142444470.
The previous prime is 31142444467. The next prime is 31142444477. The reversal of 31142444471 is 17444424113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31142444471 - 22 = 31142444467 is a prime.
It is a super-3 number, since 3×311424444713 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31142444477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571222235 + 15571222236.
It is an arithmetic number, because the mean of its divisors is an integer number (15571222236).
Almost surely, 231142444471 is an apocalyptic number.
31142444471 is a deficient number, since it is larger than the sum of its proper divisors (1).
31142444471 is an equidigital number, since it uses as much as digits as its factorization.
31142444471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 43008, while the sum is 35.
Adding to 31142444471 its reverse (17444424113), we get a palindrome (48586868584).
The spelling of 31142444471 in words is "thirty-one billion, one hundred forty-two million, four hundred forty-four thousand, four hundred seventy-one".
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