Base | Representation |
---|---|
bin | 10010100011111… |
… | …111100111001001 |
3 | 210201000001110002 |
4 | 102203333213021 |
5 | 1114211103411 |
6 | 50522532345 |
7 | 10501034003 |
oct | 2243774711 |
9 | 721001402 |
10 | 311425481 |
11 | 14a878634 |
12 | 883670b5 |
13 | 4c69b443 |
14 | 2d509373 |
15 | 1c51933b |
hex | 128ff9c9 |
311425481 has 2 divisors, whose sum is σ = 311425482. Its totient is φ = 311425480.
The previous prime is 311425427. The next prime is 311425487. The reversal of 311425481 is 184524113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 240529081 + 70896400 = 15509^2 + 8420^2 .
It is a cyclic number.
It is not a de Polignac number, because 311425481 - 210 = 311424457 is a prime.
It is a super-2 number, since 2×3114254812 = 193971660432162722, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (311425487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155712740 + 155712741.
It is an arithmetic number, because the mean of its divisors is an integer number (155712741).
Almost surely, 2311425481 is an apocalyptic number.
It is an amenable number.
311425481 is a deficient number, since it is larger than the sum of its proper divisors (1).
311425481 is an equidigital number, since it uses as much as digits as its factorization.
311425481 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3840, while the sum is 29.
The square root of 311425481 is about 17647.2513723809. The cubic root of 311425481 is about 677.8257261002.
Adding to 311425481 its reverse (184524113), we get a palindrome (495949594).
The spelling of 311425481 in words is "three hundred eleven million, four hundred twenty-five thousand, four hundred eighty-one".
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