311430001201301 has 4 divisors (see below), whose sum is σ = 311430425409600. Its totient is φ = 311429576993004.

The previous prime is 311430001201259. The next prime is 311430001201303. The reversal of 311430001201301 is 103102100034113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311430001201301 - 2¹⁰ = 311430001200277 is a prime.

It is a super-3 number, since 3×311430001201301³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311430001201303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211001021 + ... + 212471858.

It is an arithmetic number, because the mean of its divisors is an integer number (77857606352400).

Almost surely, 2^{311430001201301} is an apocalyptic number.

It is an amenable number.

311430001201301 is a deficient number, since it is larger than the sum of its proper divisors (424208299).

311430001201301 is an equidigital number, since it uses as much as digits as its factorization.

311430001201301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 424208298.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 311430001201301 its reverse (103102100034113), we get a palindrome (414532101235414).

The spelling of 311430001201301 in words is "three hundred eleven trillion, four hundred thirty billion, one million, two hundred one thousand, three hundred one".