31143001141 has 4 divisors (see below), whose sum is σ = 35592001312. Its totient is φ = 26694000972.

The previous prime is 31143001051. The next prime is 31143001147. The reversal of 31143001141 is 14110034113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31143001141 - 2¹¹ = 31142999093 is a prime.

It is a super-3 number, since 3×31143001141³ (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31143001147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2224500075 + ... + 2224500088.

It is an arithmetic number, because the mean of its divisors is an integer number (8898000328).

Almost surely, 2^31143001141 is an apocalyptic number.

It is an amenable number.

31143001141 is a deficient number, since it is larger than the sum of its proper divisors (4449000171).

31143001141 is an equidigital number, since it uses as much as digits as its factorization.

31143001141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4449000170.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 31143001141 its reverse (14110034113), we get a palindrome (45253035254).

The spelling of 31143001141 in words is "thirty-one billion, one hundred forty-three million, one thousand, one hundred forty-one".