311430041111041 has 4 divisors (see below), whose sum is σ = 311430413164500. Its totient is φ = 311429669057584.

The previous prime is 311430041110973. The next prime is 311430041111087. The reversal of 311430041111041 is 140111140034113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 228501316387600 + 82928724723441 = 15116260^2 + 9106521^2 .

It is a cyclic number.

It is not a de Polignac number, because 311430041111041 - 2²³ = 311430032722433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311430041110997 and 311430041111015.

It is not an unprimeable number, because it can be changed into a prime (311430041111341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184768306 + ... + 186446203.

It is an arithmetic number, because the mean of its divisors is an integer number (77857603291125).

Almost surely, 2^{311430041111041} is an apocalyptic number.

It is an amenable number.

311430041111041 is a deficient number, since it is larger than the sum of its proper divisors (372053459).

311430041111041 is an equidigital number, since it uses as much as digits as its factorization.

311430041111041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 372053458.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 311430041111041 its reverse (140111140034113), we get a palindrome (451541181145154).

The spelling of 311430041111041 in words is "three hundred eleven trillion, four hundred thirty billion, forty-one million, one hundred eleven thousand, forty-one".