3114300433241 has 2 divisors, whose sum is σ = 3114300433242. Its totient is φ = 3114300433240.

The previous prime is 3114300433169. The next prime is 3114300433259. The reversal of 3114300433241 is 1423340034113.

It is a happy number.

3114300433241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1599010830400 + 1515289602841 = 1264520^2 + 1230971^2 .

It is an emirp because it is prime and its reverse (1423340034113) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3114300433241 is a prime.

It is a super-4 number, since 4×3114300433241⁴ (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is not a weakly prime, because it can be changed into another prime (3114300453241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557150216620 + 1557150216621.

It is an arithmetic number, because the mean of its divisors is an integer number (1557150216621).

Almost surely, 2^{3114300433241} is an apocalyptic number.

It is an amenable number.

3114300433241 is a deficient number, since it is larger than the sum of its proper divisors (1).

3114300433241 is an equidigital number, since it uses as much as digits as its factorization.

3114300433241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 3114300433241 its reverse (1423340034113), we get a palindrome (4537640467354).

The spelling of 3114300433241 in words is "three trillion, one hundred fourteen billion, three hundred million, four hundred thirty-three thousand, two hundred forty-one".