Base | Representation |
---|---|
bin | 100011011001111101000010… |
… | …0011111010000101000111101 |
3 | 1111211200110001011122021011121 |
4 | 1012303322010133100220331 |
5 | 311304433224130420333 |
6 | 3022205034432350541 |
7 | 122412045122456152 |
oct | 10663720437205075 |
9 | 1454613034567147 |
10 | 311430301420093 |
11 | 9025a9381a9179 |
12 | 2ab193419a5451 |
13 | 104a099cb0657b |
14 | 56c944263c229 |
15 | 260103bc2a32d |
hex | 11b3e847d0a3d |
311430301420093 has 2 divisors, whose sum is σ = 311430301420094. Its totient is φ = 311430301420092.
The previous prime is 311430301420079. The next prime is 311430301420171. The reversal of 311430301420093 is 390024103034113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 241294064851449 + 70136236568644 = 15533643^2 + 8374738^2 .
It is an emirp because it is prime and its reverse (390024103034113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311430301420093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311430301420033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715150710046 + 155715150710047.
It is an arithmetic number, because the mean of its divisors is an integer number (155715150710047).
Almost surely, 2311430301420093 is an apocalyptic number.
It is an amenable number.
311430301420093 is a deficient number, since it is larger than the sum of its proper divisors (1).
311430301420093 is an equidigital number, since it uses as much as digits as its factorization.
311430301420093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 34.
The spelling of 311430301420093 in words is "three hundred eleven trillion, four hundred thirty billion, three hundred one million, four hundred twenty thousand, ninety-three".
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