Base | Representation |
---|---|
bin | 100011011001111101000010… |
… | …0101001111101001101100111 |
3 | 1111211200110001100220201112211 |
4 | 1012303322010221331031213 |
5 | 311304433230340132403 |
6 | 3022205035012424251 |
7 | 122412045155345131 |
oct | 10663720451751547 |
9 | 1454613040821484 |
10 | 311430304224103 |
11 | 9025a939843939 |
12 | 2ab19342918087 |
13 | 104a09a057894c |
14 | 56c9442b6c051 |
15 | 260103c0d106d |
hex | 11b3e84a7d367 |
311430304224103 has 4 divisors (see below), whose sum is σ = 311640304430728. Its totient is φ = 311220304017480.
The previous prime is 311430304224101. The next prime is 311430304224107. The reversal of 311430304224103 is 301422403034113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 311430304224103 - 21 = 311430304224101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311430304224101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105000101088 + ... + 105000104053.
It is an arithmetic number, because the mean of its divisors is an integer number (77910076107682).
Almost surely, 2311430304224103 is an apocalyptic number.
311430304224103 is a deficient number, since it is larger than the sum of its proper divisors (210000206625).
311430304224103 is a wasteful number, since it uses less digits than its factorization.
311430304224103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 210000206624.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 311430304224103 its reverse (301422403034113), we get a palindrome (612852707258216).
The spelling of 311430304224103 in words is "three hundred eleven trillion, four hundred thirty billion, three hundred four million, two hundred twenty-four thousand, one hundred three".
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