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31143124231 is a prime number
BaseRepresentation
bin11101000000010001…
…100101110100000111
32222101102021122000121
4131000101211310013
51002240114433411
622150145122411
72151520121362
oct350021456407
988342248017
1031143124231
11122315331aa
126051929407
132c2416467b
1417161b10d9
15c2417c571
hex740465d07

31143124231 has 2 divisors, whose sum is σ = 31143124232. Its totient is φ = 31143124230.

The previous prime is 31143124189. The next prime is 31143124247. The reversal of 31143124231 is 13242134113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31143124231 - 29 = 31143123719 is a prime.

It is a super-2 number, since 2×311431242312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31143124196 and 31143124205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31143124291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571562115 + 15571562116.

It is an arithmetic number, because the mean of its divisors is an integer number (15571562116).

Almost surely, 231143124231 is an apocalyptic number.

31143124231 is a deficient number, since it is larger than the sum of its proper divisors (1).

31143124231 is an equidigital number, since it uses as much as digits as its factorization.

31143124231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 25.

Adding to 31143124231 its reverse (13242134113), we get a palindrome (44385258344).

The spelling of 31143124231 in words is "thirty-one billion, one hundred forty-three million, one hundred twenty-four thousand, two hundred thirty-one".