Base | Representation |
---|---|
bin | 100011011001111101100000… |
… | …0100111100111001000100111 |
3 | 1111211200112122110220202010122 |
4 | 1012303323000213213020213 |
5 | 311304442310410223333 |
6 | 3022205322511112155 |
7 | 122412112122352664 |
oct | 10663730047471047 |
9 | 1454615573822118 |
10 | 311431310242343 |
11 | 902603056a8275 |
12 | 2ab1958381265b |
13 | 104a0b00b12205 |
14 | 56c94da604a6b |
15 | 260109a5a0798 |
hex | 11b3ec09e7227 |
311431310242343 has 2 divisors, whose sum is σ = 311431310242344. Its totient is φ = 311431310242342.
The previous prime is 311431310242321. The next prime is 311431310242397. The reversal of 311431310242343 is 343242013134113.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311431310242343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311431310242303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715655121171 + 155715655121172.
It is an arithmetic number, because the mean of its divisors is an integer number (155715655121172).
Almost surely, 2311431310242343 is an apocalyptic number.
311431310242343 is a deficient number, since it is larger than the sum of its proper divisors (1).
311431310242343 is an equidigital number, since it uses as much as digits as its factorization.
311431310242343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 311431310242343 its reverse (343242013134113), we get a palindrome (654673323376456).
The spelling of 311431310242343 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred ten million, two hundred forty-two thousand, three hundred forty-three".
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