3114313401111 has 32 divisors (see below), whose sum is σ = 4646411658240. Its totient is φ = 1839488227200.

The previous prime is 3114313401097. The next prime is 3114313401239. The reversal of 3114313401111 is 1111043134113.

3114313401111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 3114313401111 - 2¹⁵ = 3114313368343 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3114313406111) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6877375 + ... + 7316208.

It is an arithmetic number, because the mean of its divisors is an integer number (145200364320).

Almost surely, 2^{3114313401111} is an apocalyptic number.

3114313401111 is a deficient number, since it is larger than the sum of its proper divisors (1532098257129).

3114313401111 is a wasteful number, since it uses less digits than its factorization.

3114313401111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14193767.

The product of its (nonzero) digits is 432, while the sum is 24.

Adding to 3114313401111 its reverse (1111043134113), we get a palindrome (4225356535224).

The spelling of 3114313401111 in words is "three trillion, one hundred fourteen billion, three hundred thirteen million, four hundred one thousand, one hundred eleven".