Base | Representation |
---|---|
bin | 100011011001111101110101… |
… | …0011101011111010110101111 |
3 | 1111211200121110101211112001200 |
4 | 1012303323222131133112233 |
5 | 311310000230112411421 |
6 | 3022205520305140543 |
7 | 122412135405232251 |
oct | 10663735235372657 |
9 | 1454617411745050 |
10 | 311432012232111 |
11 | 90260635986601 |
12 | 2ab1973a92a753 |
13 | 104a0bb339a184 |
14 | 56c9565939cd1 |
15 | 26010dc017726 |
hex | 11b3eea75f5af |
311432012232111 has 12 divisors (see below), whose sum is σ = 450141608420088. Its totient is φ = 207485017551504.
The previous prime is 311432012232073. The next prime is 311432012232181. The reversal of 311432012232111 is 111232210234113.
311432012232111 is a `hidden beast` number, since 3 + 1 + 1 + 4 + 320 + 1 + 2 + 2 + 321 + 11 = 666.
It is a de Polignac number, because none of the positive numbers 2k-311432012232111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311432012232181) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11360313580 + ... + 11360340993.
It is an arithmetic number, because the mean of its divisors is an integer number (37511800701674).
Almost surely, 2311432012232111 is an apocalyptic number.
311432012232111 is a deficient number, since it is larger than the sum of its proper divisors (138709596187977).
311432012232111 is a wasteful number, since it uses less digits than its factorization.
311432012232111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22720656102 (or 22720656099 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 311432012232111 its reverse (111232210234113), we get a palindrome (422664222466224).
The spelling of 311432012232111 in words is "three hundred eleven trillion, four hundred thirty-two billion, twelve million, two hundred thirty-two thousand, one hundred eleven".
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