Base | Representation |
---|---|
bin | 11101000000010010… |
… | …000010011001101001 |
3 | 2222101102111120122021 |
4 | 131000102002121221 |
5 | 1002240132210241 |
6 | 22150151424441 |
7 | 2151521116633 |
oct | 350022023151 |
9 | 88342446567 |
10 | 31143241321 |
11 | 12231603175 |
12 | 6051985121 |
13 | 2c241a5a5a |
14 | 1716201a53 |
15 | c241a20d1 |
hex | 740482669 |
31143241321 has 2 divisors, whose sum is σ = 31143241322. Its totient is φ = 31143241320.
The previous prime is 31143241313. The next prime is 31143241343. The reversal of 31143241321 is 12314234113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31129662096 + 13579225 = 176436^2 + 3685^2 .
It is a cyclic number.
It is not a de Polignac number, because 31143241321 - 23 = 31143241313 is a prime.
It is not a weakly prime, because it can be changed into another prime (31143241351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571620660 + 15571620661.
It is an arithmetic number, because the mean of its divisors is an integer number (15571620661).
Almost surely, 231143241321 is an apocalyptic number.
It is an amenable number.
31143241321 is a deficient number, since it is larger than the sum of its proper divisors (1).
31143241321 is an equidigital number, since it uses as much as digits as its factorization.
31143241321 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 25.
Adding to 31143241321 its reverse (12314234113), we get a palindrome (43457475434).
The spelling of 31143241321 in words is "thirty-one billion, one hundred forty-three million, two hundred forty-one thousand, three hundred twenty-one".
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