Base | Representation |
---|---|
bin | 11101000000010100… |
… | …011011011010010011 |
3 | 2222101110200102100111 |
4 | 131000110123122103 |
5 | 1002240312234201 |
6 | 22150213102151 |
7 | 2151526340062 |
oct | 350024333223 |
9 | 88343612314 |
10 | 31143868051 |
11 | 122319a102a |
12 | 6052027957 |
13 | 2c243650ba |
14 | 17163261d9 |
15 | c24277b51 |
hex | 74051b693 |
31143868051 has 2 divisors, whose sum is σ = 31143868052. Its totient is φ = 31143868050.
The previous prime is 31143868033. The next prime is 31143868057. The reversal of 31143868051 is 15086834113.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31143868051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31143867995 and 31143868013.
It is not a weakly prime, because it can be changed into another prime (31143868057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571934025 + 15571934026.
It is an arithmetic number, because the mean of its divisors is an integer number (15571934026).
Almost surely, 231143868051 is an apocalyptic number.
31143868051 is a deficient number, since it is larger than the sum of its proper divisors (1).
31143868051 is an equidigital number, since it uses as much as digits as its factorization.
31143868051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 40.
The spelling of 31143868051 in words is "thirty-one billion, one hundred forty-three million, eight hundred sixty-eight thousand, fifty-one".
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