311440321333041 has 4 divisors (see below), whose sum is σ = 415253761777392. Its totient is φ = 207626880888692.

The previous prime is 311440321333039. The next prime is 311440321333061. The reversal of 311440321333041 is 140333123044113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311440321333041 - 2¹ = 311440321333039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311440321332993 and 311440321333011.

It is not an unprimeable number, because it can be changed into a prime (311440321333061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51906720222171 + ... + 51906720222176.

It is an arithmetic number, because the mean of its divisors is an integer number (103813440444348).

Almost surely, 2^{311440321333041} is an apocalyptic number.

It is an amenable number.

311440321333041 is a deficient number, since it is larger than the sum of its proper divisors (103813440444351).

311440321333041 is a wasteful number, since it uses less digits than its factorization.

311440321333041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103813440444350.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 311440321333041 its reverse (140333123044113), we get a palindrome (451773444377154).

The spelling of 311440321333041 in words is "three hundred eleven trillion, four hundred forty billion, three hundred twenty-one million, three hundred thirty-three thousand, forty-one".