311440331400041 has 2 divisors, whose sum is σ = 311440331400042. Its totient is φ = 311440331400040.

The previous prime is 311440331399969. The next prime is 311440331400043. The reversal of 311440331400041 is 140004133044113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 243131825509225 + 68308505890816 = 15592685^2 + 8264896^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311440331400041 is a prime.

Together with 311440331400043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 311440331399977 and 311440331400013.

It is not a weakly prime, because it can be changed into another prime (311440331400043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155720165700020 + 155720165700021.

It is an arithmetic number, because the mean of its divisors is an integer number (155720165700021).

Almost surely, 2^{311440331400041} is an apocalyptic number.

It is an amenable number.

311440331400041 is a deficient number, since it is larger than the sum of its proper divisors (1).

311440331400041 is an equidigital number, since it uses as much as digits as its factorization.

311440331400041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 311440331400041 its reverse (140004133044113), we get a palindrome (451444464444154).

The spelling of 311440331400041 in words is "three hundred eleven trillion, four hundred forty billion, three hundred thirty-one million, four hundred thousand, forty-one".