Base | Representation |
---|---|
bin | 101101010100100010000… |
… | …001111001011101010001 |
3 | 102000201212102211220211212 |
4 | 231110202001321131101 |
5 | 402011314041244213 |
6 | 10342425032345505 |
7 | 441003200005130 |
oct | 55244201713521 |
9 | 12021772756755 |
10 | 3114422212433 |
11 | aa0901167504 |
12 | 423719845295 |
13 | 1978c526924c |
14 | aaa4b537917 |
15 | 5602ebb19a8 |
hex | 2d522079751 |
3114422212433 has 32 divisors (see below), whose sum is σ = 3704884022784. Its totient is φ = 2562463475712.
The previous prime is 3114422212417. The next prime is 3114422212441. The reversal of 3114422212433 is 3342122244113.
It is a happy number.
It is not a de Polignac number, because 3114422212433 - 24 = 3114422212417 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3114422212433.
It is not an unprimeable number, because it can be changed into a prime (3114422212403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7768460 + ... + 8159522.
It is an arithmetic number, because the mean of its divisors is an integer number (115777625712).
Almost surely, 23114422212433 is an apocalyptic number.
It is an amenable number.
3114422212433 is a deficient number, since it is larger than the sum of its proper divisors (590461810351).
3114422212433 is a wasteful number, since it uses less digits than its factorization.
3114422212433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 391521.
The product of its digits is 27648, while the sum is 32.
Adding to 3114422212433 its reverse (3342122244113), we get a palindrome (6456544456546).
The spelling of 3114422212433 in words is "three trillion, one hundred fourteen billion, four hundred twenty-two million, two hundred twelve thousand, four hundred thirty-three".
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